Chapter 4 - Discrete Random Variables - Exercises 4.15 - 4.33 - Applying the Concepts - Intermediate - Page 188: 4.26b

P(0) = (5!) (.35)^{0} (.65)^{5-0} / (0!) (5-0)! = 0.1160 P(1) = (5!) (.35)^{1} (.65)^{5-1} / (1!) (5-1)! = 0.3124 P(2) = (5!) (.35)^{2} (.65)^{5-2} / (2!) (5-2)! = 0.3364 P(3) = (5!) (.35)^{3} (.65)^{5-3} / (3!) (5-3)! = 0.1811 P(4) = (5!) (.35)^{4} (.65)^{5-4} / (4!) (5-4)! = 0.0488 P(5) = (5!) (.35)^{5} (.65)^{5-5} / (4!) (5-5)! = 0.0053

As given in answer