Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 3 - Probability - Exercises 3.35 - 3.62 - Learning the Mechanics: 3.48a

Answer

Three mutually exclusive events can be E_{1} = Getting exactly one head E_{2} = Getting exactly two heads E_{3} = Getting exactly three heads P(E_{1}) = {HTT, THT, TTH} = 3/8 P(E_{2}) = {HHT, HTH, THH} = 3/8 P(E_{3}) = {HHH} = 1/8 P(A) = P(E_{1}) + P(E_{2}) + P(E_{3}) = 3/8 + 3/8 + 1/8 = 7/8

Work Step by Step

As given in answer
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.