Answer
a. $σ_p̂$=$\sqrt \frac{0.68*0.32}{600}$=0.019
z= $\frac{0.68-0.7}{0.019}$ =-1.05
α = 0.01,α/2 = 0.005, From the table, critical value =2.576
Rejection region = z< -2.576 or z> 2.576
Non rejection region = [-2.576, 2.576]
The value z = -1.05 falls within the non-rejection region, hence we failed to reject the null hypothesis.
b. $σ_p̂$=$\sqrt \frac{0.76*0.24}{600}$=0.017
z= $\frac{0.76-0.7}{0.017}$ =3.53
α = 0.01,α/2 = 0.005, From the table, critical value = 2.576
Rejection region = z< -2.576 or z> 2.576
Non rejection region = [-2.576, 2.576]
The value z = 3.53 falls at the rejection region, hence we reject the null hypothesis.
Work Step by Step
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