Answer
$\bar{x}$ = 248.1/12=20.675 , μ=18, s = $\sqrt \frac{5633.53-(248.1^{2}}{11}=6.7693$, $σ_\bar{s}$=$\frac{6.7693}{\sqrt 12}$=2.041, n=12
α = 0.1 / 2 = 0.05 , df = 12-1=11, critical value= 1.796
t ==$\frac{\bar{x}-μ }{σ_\bar{s}}$=$\frac{20.675-18}{2.041}$
= 1.31
H0: μ=18
H1: μ !=18
for α = 0
Non rejection region = [-1.796,1.796]
Rejection region = t 1.796
-1.796 < t < 1.796, we failed to reject H0 and conclude the average amount of time spent by American adults on leisure activities remain unchanged.
Work Step by Step
--
