Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 3 - Probability - Section 3.1 Basic Concepts of Probability and Counting - Exercises - Page 142: 55

Answer

(a) 1000 (b) 0.001 (c) 0.999

Work Step by Step

number of possible access codes = 10^{3} = 1000 Probability of randomly selecting the correct access code on the first try = 1/1000 = 0.001 probability of not selecting the correct access code on the first try = 1 - 1/1000 = 0.999
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.