Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 7 - Estimates and Sample Sizes - Review - Chapter Quick Quiz - Page 373: 5



Work Step by Step

$\alpha=1-0.9=0.1.$ Then, by using the table, the critical value: $z_{\alpha/2}=z_{0.05}=1.645.$ $\hat{p}$ is unknown, hence:$n=\frac{z^2_{\frac{\alpha}{2}}\cdot0.25}{E^2}=\frac{1.645^2\cdot0.25}{0.03^2}=752.$
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