## Elementary Statistics (12th Edition)

$\frac{1}{22957480}$
Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{53!}{(53-6)!6}=22957480$. We also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{22957480}$.