Answer
a. 0.0378
b. 0.01
c. 0.0516
d. 0.175
Work Step by Step
a. p (x=5) = f (5) = 0.0378
b. p (x\leq3) = f (0) + f (1) + f (2) + f (3) = 0.01
c. e^-20 x 20^15 / 15! = 0.0516
d. e^-5 x 5^5 / 5! = 0.175
Applied Statistics and Probability for Engineers, 6th Edition
by Montgomery, Douglas C.; Runger, George C.
Published by
Wiley
ISBN 10:
1118539710
ISBN 13:
978-1-11853-971-2
Chapter 3 - Section 3-9 - Poisson Distribution - Exercises - Page 102: 3-160
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