Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-5 - Multiplication and Total Probability Rules - Exercises - Page 48: 2-128

Answer

See below.

Work Step by Step

a) $P(induced \ substance)=P(induced \ substance|outside \ factors)P(outside \ factors)=0.13\cdot0.73=0.0949$ b) $P(disease \ or \ infection)=P(disease \ or \ infection|natural\ occurence)P(natural\ occurence)=(0.27+0.17)\cdot0.87=0.3828$
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