Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 2 - Section 2-4 - Conditional Probability - Exercises - Page 43: 2-99

Answer

$a) \frac{86}{100}$ $b) \frac{79}{100}$ $c) \frac{70}{79}$ $d) \frac{70}{86}$

Work Step by Step

a) P(A)= No. of favourable outcomes$\div$ Total no. of outcomes= $\frac{70+16}{70+16+9+5}=\frac{86}{100}$ b) P(B)= $\frac{70+9}{100}=\frac{79}{100}$ c) $P(A|B)= \frac{P(A\cap B)}{P(B)}=\frac{\frac{70}{100}}{\frac{79}{100}}=\frac{70}{79}$ d) $P(B|A)=\frac{P(A\cap B)}{P(A)}=\frac{\frac{70}{100}}{\frac{86}{100}}=\frac{70}{86}$
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