Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 530: 80

Answer

1158 ft

Work Step by Step

Step 1. Let $h$ represent the height of the building, and Let point P be the bottom of the building. Step 2. From the definition of tangent function we have $\frac{h}{AP}=tan24.1^{\circ}\approx0.447$, thus $AP=h/0.447=2.236h$ Step 3. Similarly, $\frac{h}{BP}=tan30.2^{\circ}\approx0.582$, thus $BP=h/0.582=1.718h$ Step 4 Since $AB=600ft$, we have $AB=AP-BP=2.236h-1.718h=0.518h=600$ which gives $h\approx1158ft$
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