Answer
$f(x) = (x^3 - 3x^2 +4)$
Work Step by Step
The zeros of this graph are at (-1, 0) and (2,0).
At (2,0) , the graph "bounces" at that point, so that root is a zero with even multiplicity, so it will be to the power of two
Thus the polynomial will be $(x+1)(x-2)^2$
$f(x) = (x+1)(x^2 - 4x + 4)$
$f(x) = (x^3 - 3x^2 +4)$
