Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Modeling with Functions - Problems - Page 240: 8

Answer

$SA = 6V^{\frac{2}{3}}$

Work Step by Step

Surface Area of a cube = $SA = 6x^2$ Volume of a cube = $V = x^3$ Thus $x = V^{\frac{1}{3}}$ Substitute x for that in the SA formula $SA = 6{V^{\frac{1}{3}}}^{2}$ $SA = 6V^{\frac{2}{3}}$
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