Answer
$3.4722W/m^2$
Work Step by Step
As per the given problem, we have:
$B=\dfrac{kL}{d^2}$
Here, $k$ is defined as constant of proportionality
Plug the given data in the above expression, we get
$B=(0.080)\dfrac{2.5\times 10^{26}}{(2.4 \times 10^{19})^2}=3.4722W/m^2$
