Answer
$(x+1)^2=6(y-3)$
See graph.
Work Step by Step
1. Known a parabola with focus $(-1,4.5)$, vertex $(-1,3)$, we can find it opens upward with a possible equation $(x+1)^2=4p(y-3)$
2. With $p=4.5-3=1.5$, we have $(x+1)^2=6(y-3)$
3. See graph.