Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

by Sullivan III, Michael

Published by Pearson

ISBN 10: 0-32193-104-1

ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.7 Systems of Inequalities - 10.7 Assess Your Understanding - Page 805: 64

Answer

See below.

Work Step by Step

Given $f(x)=6x^2+5x$, we have $f(-1)=6(-1)^2+5(-1)-6=-5\lt0$ and $f(2)=6(2)^2+5(2)-6=28\gt0$. Based on the Intermediate Value Theorem, there is a zero within $[-1,2]$

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