Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 736: 73

Answer

$r=0.06= 6 \% $ and $Y=9000$

Work Step by Step

We need to solve the system of equations as follows: $$0.06Y−5000r=240~~~~(1) \\ 0.06Y+6000r=900~~~~(2)$$ We will multiply equation (1) by $-1$. $$-0.06Y+5000r=-240~~~~(3)$$ Now, add equations (2) and (3) to eliminate $Y$. $$0.06Y+6000r−0.06Y+5000r=900−240~~~~(4)\\ 11000 r =660 \\ r=0.06= 6 \%$$ Now, back substitute the value of $r$ into Equation (1) to solve for $Y$: $$0.06Y-5000 (0.06)=240 \\ 0.06Y =240+300 \\ 0.06 Y =540 \\ Y=\dfrac{540}{0.06} \\ Y=9000$$ Therefore, our results are: $r=0.06= 6 \% $ and $Y=9000$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.