Answer
$\{(-6,7)\}$
Work Step by Step
Use Cramer's rule, we have:
1. $D=\begin{vmatrix} 2 & -3 \\ 4 & 5 \end{vmatrix}=(2)(5)-(-3)(4)=22$
2. $D_x=\begin{vmatrix} -33 & -3 \\ 11 & 5 \end{vmatrix}=(-33)(5)-(-3)(11)=-132$
3. $D_y=\begin{vmatrix} 2 & -33 \\ 4 & 11 \end{vmatrix}=(2)(11)-(-33)(4)=154$
4. $x=\frac{D_x}{D}=\frac{-132}{22}=-6$ and $y=\frac{D_y}{D}=\frac{154}{22}=7$
5. Thus the solution set is $\{(-6,7)\}$
