## Precalculus (6th Edition)

$E$ domain: $(-\infty, +\infty)$ range: $[0, \infty)$
The graph of the squaring function $f(x)=x^2$ is a parabola (U-shaped) that opens upward (refer to page 250 of the textbook). Thus, the graph of $f(x)=x^2$ is the one in Option E. The graph covers all x-values so the domain is $(-\infty, +\infty)$. The graph covers the y-values from $0$ and above so the range is $[0, \infty)$.