Answer
$a_1= 1, a_2= -\frac{1}{2}, a_3= \frac{1}{4}, a_4= -\frac{1}{8}, a_5= \frac{1}{16}, $ geometric.
Work Step by Step
1. Given $a_n=-2(-\frac{1}{2})^n$, we have: $a_1=-2(-\frac{1}{2})^1=1, a_2=-2(-\frac{1}{2})^2=-\frac{1}{2}, a_3=-2(-\frac{1}{2})^3=\frac{1}{4}, a_4=-2(-\frac{1}{2})^4=-\frac{1}{8}, a_5=-2(-\frac{1}{2})^5=\frac{1}{16}, $
2. We can identify the sequence as geometric.
