Answer
See graph and explanations.
Work Step by Step
Rewrite the equation as $\frac{x^2}{9}+\frac{y^2}{4}=1$, we can identify it as an ellipse with center $(0,0)$, vertices $(\pm3,0)$. As $a=3,b=2$, we have $c=\sqrt {a^2-b^2}=\sqrt 5$ and the foci at $(\pm\sqrt 5,0)$. See graph.
