Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.3 The Law of Cosines - 8.3 Assess Your Understanding - Page 538: 43

Answer

$\approx165.3\text {yd}$

Work Step by Step

By the law of cosines: $c^2=a^2+b^2-2ab\cdot \cos(C)$, where $C$ is the included angle of $a$ and $b$. Hence, if the distance between the ball and the center of the green is $x$, then: $x^2=35^2+150^2-2(35)(150)\cos{110^\circ}\\x^2\approx27316.2115\\x=\sqrt{27316.2115}\\ x\approx165.3$
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