Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 531: 33

Answer

There is no triangle with these values.

Work Step by Step

First, we can only calculate the angle $A$ with the help of the Law of Sines: $\frac{sin(A)}{a}=\frac{sin(C)}{c}$ $\frac{sin(100°)}{1}=\frac{sin(A)}{2}$ $sin(A)=1.96$ This equation means, that there is no triangle with these values. That's because the range of the sine function is: $-1\le \sin x\le 1$
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