Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Chapter Test - Page 508: 29

Answer

$0.253, 2.889$

Work Step by Step

Step 1. $4sin^2\theta+7sin\theta-2=0 \longrightarrow (4sin\theta-1)(sin\theta+2)=0\longrightarrow sin\theta=\frac{1}{4}$ and $sin\theta=-2$ Step 2. For $sin\theta=\frac{1}{4}$, we have $\theta=2k\pi+sin^{-1}(\frac{1}{4})\approx 2k\pi+0.253$ and $\theta\approx 2k\pi+2.889$ Step 3. Within $[0,2\pi)$, we have $\theta=0.253, 2.889$
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