Answer
$4^{1}$ $\times$ ($2^{3}$ - 8 ) = 0
Work Step by Step
$4^{1}$ $\times$ ($2^{3}$ - 8 ) =
4 $\times$ (8 - 8) = (Work inside the parenthesis first )
4 $\times$ 0 =
0
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 9 - Section 9.2 - Perimeter - Exercise Set - Page 623: 60
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