Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.1 - Lines and Angles - Exercise Set: 61

Answer

$\frac{5}{6}$

Work Step by Step

Convert to improper like fractions to subtract. $3\frac{1}{3}-2\frac{1}{2}=3\frac{1\times2}{3\times2}-2\frac{1\times3}{2\times3}=3\frac{2}{6}-2\frac{3}{6}=\frac{20}{6}-\frac{15}{6}=\frac{5}{6}$
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