Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Test - Page 464: 15

Answer

y = $\frac{7}{3}$

Work Step by Step

To solve, simply cross multiply across the fractions: Multiply the denominator of one fraction times the numerator of the other and vice versa: ($\frac{3}{7}$)y = 4($\frac{1}{4}$) $\frac{3}{7}$y = 1 Now, to get y by itself, multiply both sides by the reciprocal of $\frac{3}{7}$, which is $\frac{7}{3}$ $\frac{7}{3}$($\frac{3}{7}$y) = $\frac{7}{3}$(1) y = $\frac{7}{3}$
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