Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 2 - Review - Page 157: 129



Work Step by Step

$\frac{-|-14|-6}{7+2(-3)}$ $\longrightarrow$multiply =$\frac{-|-14|-6}{7+(-6)}$ $\longrightarrow$resolve absolute value =$\frac{-14-6}{7+(-6)}$ $\longrightarrow$simplify numerator and denominator =$\frac{-20}{1}$ $\longrightarrow$simplify =$-20$
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