Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.6 Negations of Conditional Statements and De Morgan's Law - Concept and Vocabulary Check - Page 177: 5

Answer

False.

Work Step by Step

False, the negation of $p\rightarrow q$ is $p\land \sim q$, which is $p\rightarrow \sim q$
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