Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - Review Exercises - Page 698: 52

Answer

6

Work Step by Step

$-\frac{4}{5}\div(-\frac{2}{15})=-\frac{4}{5}\times\frac{1}{-\frac{2}{15}}=-\frac{4}{5}\times-\frac{15}{2}=\frac{4\times15}{5\times2}=\frac{60}{10}=\frac{60\div10}{10\div10}=6$ Both fractions have the same sign, so the result will be positive.
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