Answer
$d=\frac{7}{3}$
Work Step by Step
We are given the equation $d+\frac{2}{3}=3$.
Subtract $\frac{2}{3}$ from both sides.
$d+\frac{2}{3}-\frac{2}{3}=3-\frac{2}{3}$
$d+0=3-\frac{2}{3}=\frac{9}{3}-\frac{2}{3}=\frac{9-2}{3}=\frac{7}{3}$
$d+0=\frac{7}{3}$
Therefore, $d=\frac{7}{3}$.