## Basic College Mathematics (9th Edition)

A = $\frac{55}{2}$ $yd^{2}$ or 27$\frac{1}{2}$ $yd^{2}$
A = $\frac{1}{2}$bh b =15 ft, h = 3 ft In this formula, b is the length of the base of the triangle and h is the height of the triangle. What is the area if b is 5 yd and h is 11 yd? A = $\frac{1}{2}$bh Evaluate the formula by replacing b with 5 yd and h with 11 yd. A = $\frac{1}{2}$ * 5 yd * 11 yd = $\frac{55}{2}$ $yd^{2}$ Convert it into mixed fraction 27$\frac{1}{2}$ $yd^{2}$ The area of the triangle is $\frac{55}{2}$ $yd^{2}$ or 27$\frac{1}{2}$ $yd^{2}$