Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 697: 63

Answer

$= -1$

Work Step by Step

$=\frac{3-(5^{2} - 4^{2})}{14 + 24\div (-3)}$ $=\frac{3-(25-16)}{14 -8}$ $=\frac{3-9}{14 -8}$ $=\frac{-6}{6}$ $=-1$
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