Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.7 Solving Equations with Several Steps - 9.7 Exercises - Page 677: 28


$6y-18$, $-5b+15$

Work Step by Step

The distributive property holds that $a(b+c)=ab+ac$. A. Therefore, $6(y-3)=(6\times y)+(6\times-3)=(6y)+(-18)=6y-18$. In this example, the student has forgotten to distribute the 6 to the second term in parentheses. B. Therefore, $-5(b-3)=(-5\times b)+(-5\times-3)=(-5b)+(15)=-5b+15$. In this example, the student has forgotten that multiplying the negative number outside of the parentheses by the negative second term will result in a positive product.
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