Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 553: 35

Answer

a) $P$ = 10 ft $A$ = 6 ft$^{2}$ b) $P$ = 20 ft $A$ = 24 ft$^{2}$ c) The perimeter is twice as large as the original. The area is four times larger than the original.

Work Step by Step

Area of a rectangle: $A$ = $l$$w$ Perimeter of a rectangle: $P$ = 2($l$ + $w$) a) $A$ = $l$$w$ $A$ = (3 ft)(2 ft) $A$ = 6 ft$^{2}$ $P$ = 2($l$ + $w$) $P$ = 2(3 ft + 2 ft) $P$ = 2(5 ft) $P$ = 10 ft b) $A$ = $l$$w$ $A$ = (6 ft)(4 ft) $A$ = 24 ft$^{2}$ $P$ = 2($l$ + $w$) $P$ = 2(6 ft + 4 ft) $P$ = 2(10 ft) $P$ = 20 ft
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