Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 8 - Right Triangles and Trigonometry - Mid-Chapter Quiz - Page 515: 4

Answer

$x = 9$

Work Step by Step

In a $45^{\circ}-45^{\circ}-90^{\circ}$ triangle, the hypotenuse is $\sqrt 2$ times each leg. Let's write an equation to solve for $x$, the length of a leg: $9\sqrt 2 = \sqrt 2(x)$ Divide each side by $\sqrt 2$ to solve for $x$: $x = 9$
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