Answer
$8$
Work Step by Step
The Trigonometric ratios for $sine$ function can be written as follows:
$\ Cos \theta=\dfrac{Adjacent}{hypotenuse}$
We are given that the length of Adjacent and the angle. Our aim is to compute the side of opposite to the angle.
Therefore, $\cos 41^{\circ}=\dfrac{x}{11}$
This implies that $x=11 \sin 41^{\circ} \approx 8$
