Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 3 - Parallel and Perpendicular Lines - Get Ready!: 11

Answer

8.2

Work Step by Step

Substitute the given values into the distance formula. Simplify to find the distance. $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ $d=\sqrt{(4-(-4))^2+(4-2)^2}$ $d=\sqrt{(8)^2+(2)^2}$ $d=\sqrt{64+4}$ $d=\sqrt{68}$ $d=8.2$
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