Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 13 - Probability - Mid-Chapter Quiz: 16

Answer

10

Work Step by Step

We know that: $_nC_r =\frac{_nP_r}{r!} = \frac{n!}{(n-r)!r!}$ $_{10}C_9 = \frac{10!}{(10-9)!9!}$ $\frac{ 10!}{9!}$ We also know that: $x! = x(x-1)(x-2)...(1)$ Thus, we have: 10
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