Answer
$54 \ m^2$
Work Step by Step
The area of a trapezoid is equal to half the product of the sum of the bases and the height.
Suppose $a$ and $b$ are bases and $h$ is the height of a trapezoid.
Now, the area of a trapezoid $A=\dfrac{1}{2} (a+c)(h)\\=\dfrac{1}{2} (18)(6)\\= 54 \ m^2$
