Geometry: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281159
ISBN 13: 978-0-13328-115-6

Chapter 10 - Area - 10-6 Circles and Arcs - Practice and Problem-Solving Exercises - Page 654: 15

Answer

$m\widehat{TCB}=270^{\circ}$

Work Step by Step

We must know that the measure of a minor arc is equal to the measure of its corresponding central angle. In the given question, we can see that the related minor arc of major $\widehat{TCB}$ is $\widehat{TB}$ . This implies that We have $m\widehat{TB}=m\angle TPB=90^{\circ}$. This implies that $m\widehat{TCB}=360^{\circ}-90^{\circ}$ or, $m\widehat{TCB}=270^{\circ}$
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