Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Test - Page 492: 8b

Answer

$m_{1}$=$-\frac{3}{2}$

Work Step by Step

The slope of perpendicular lines are the negative reciprocals of each other. So $\frac{2}{3}\times m_{1} = -1$ Therefore $m_{1}$=$-\frac{3}{2}$
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