Answer
$\overline{AC}$ $\ncong$ $\overline{CD}$
Work Step by Step
In part (a), we determined that $\overline{AB}$ $\cong$ $\overline{BC}$ $\cong$ $\overline{CD}$. Using the Segment Addition Postulate $\overline{AB}$ + $\overline{BC}$ $\cong$ $\overline{AC}$. Therefore, $\overline{AC}$ is twice as long as $\overline{CD}$.
