Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 5 - Section 5.3 - Proving Triangles Similar - Exercises - Page 244: 26

Answer

DE=5

Work Step by Step

$\frac{DE}{AC}$=$\frac{EB}{CB}$ $\frac{DE}{10}$=$\frac{6}{12}$ 2DE=10 DE=5
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