Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Test - Page 495: 8b

Answer

$m_{1}$=$-\frac{3}{2}$

Work Step by Step

The slope of perpendicular lines are the negative reciprocals of each other. So $\frac{2}{3}\times m_{1} = -1$ Therefore $m_{1}$=$-\frac{3}{2}$
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