Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 4 - Review Exercises - Page 206: 24

Answer

x=3 JH=30 MN=15

Work Step by Step

JH=2MN 2x$^{2}$+4x=2x$^{2}$+12 4x=12 x=3 JH=2(3)$^{2}$+4(3) JH=18+12 JH=30 MN=(3)$^{2}$+6 MN=9+6 MN=15
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