Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 2 - Section 2.1 - The Parallel Postulate and Special Angles - Exercises - Page 75: 15

Answer

x=10$^{\circ}$ m$\angle$4=110$^{\circ}$

Work Step by Step

m$\angle$3=m$\angle$6 $x^{2}$-3x=(x+4)(x-5) $x^{2}$-3x=$x^{2}$-x-20 -2x=-20 x=10$^{\circ}$ m$\angle$4=180-m$\angle$3 m$\angle$4=180-($(10)^{2}$-3(10)) m$\angle$4=180-70 m$\angle$4=110$^{\circ}$
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