Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Test - Page 527: 13a

Answer

$2$

Work Step by Step

$\sin\alpha=\frac{1}{2}$ $\csc\alpha=\frac{1}{\sin\alpha}=\frac{1}{\frac{1}{2}}=2$
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