University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.4 - Areas of Surfaces of Revolution - Exercises - Page 376: 27

Answer

$226.195 \space mm^3$

Work Step by Step

The formula to determine the surface area is as follows: $S= \int_{m}^{n} 2 \pi y \sqrt {1+(\dfrac{dy}{dx})^2} =2 \pi \times \int_{7}^{16} \sqrt {256-x^2} \times \dfrac{256}{256-x^2} dx = 904.779$ Now, the volume for each color is equal to: $(904.779) \times (0.05 \space mm) = 45.2389 mm^3$ and we multiply by $5000$ to find total woks, that is, $5000 \times ( 45.2389 mm^3) =226,195 \space mm^3$ Thus, the required amount of liters of each color is equal to: $\dfrac{226,195 \space mm^3}{1000} \approx 226.195 \space mm^3$
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