Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 17 - Second-Order Differential Equations - Review - Exercises - Page 1193: 15

Answer

No solution.

Work Step by Step

$y''+4y'+29y=0$, $y(0)=1$ and $y(\pi)=-1$ Roots are complex numbers: $\alpha \pm i \beta$, thus the General solution: $y=e^{\alpha x}[c_1cos(\beta x)+c_2sin(\beta x)]$ Plug in the given values: $y(0)=1$ and $y(\pi)=-1$ Hence, $y(0)=1$ $y(\pi)=-e^{-2\pi}\ne -1$ Since, the second boundary condition cannot be satisfied and the given problem does not have a solution.
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